15x^2+8x-35=0

Solution for 15x^2+8x-35=0 equation:

15x^2+8x-35=0

a = 15; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·15·(-35)
Δ = 2164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2164}=\sqrt{4*541}=\sqrt{4}*\sqrt{541}=2\sqrt{541}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{541}}{2*15}=\frac{-8-2\sqrt{541}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{541}}{2*15}=\frac{-8+2\sqrt{541}}{30}
$